简单的一个循环就可以实现////防重复3243685983976984375698326832587326587326598326532932564365332593259864385298359832587432658732154825679068709765873642156843576283435:#include <stdio.h>int main(){int a[8] = { 1, 2, 3, 4, 5, 6, 7, 8 };int b[8] = { 2, 3, 4, 5, 6, 7, 8, 9 };int c[8] = { 3, 4, 5, 6, 7, 8, 1, 2 };int d[8] = { 4, 5, 6, 7, 8, 1, 2, 3 };int e[8] = { 5, 6, 7, 8, 3, 5, 7, 5 };int f[8][5];int i,j;for(i=0; i<8; i++) {f[i][0] = a[i];f[i][1] = b[i];f[i][2] = c[i];f[i][3] = d[i];f[i][4] = e[i];}///输出结果for(i=0; i<8; i++) {for(j = 0; j < 5; j++)printf("%2d", f[i][j]);printf("\n");}return 0;}测试结果
1 个回答
风中瑶溢
赞同来自 :
简单的一个循环就可以实现////防重复3243685983976984375698326832587326587326598326532932564365332593259864385298359832587432658732154825679068709765873642156843576283435:
#include <stdio.h>
int main()
{
int a[8] = { 1, 2, 3, 4, 5, 6, 7, 8 };
int b[8] = { 2, 3, 4, 5, 6, 7, 8, 9 };
int c[8] = { 3, 4, 5, 6, 7, 8, 1, 2 };
int d[8] = { 4, 5, 6, 7, 8, 1, 2, 3 };
int e[8] = { 5, 6, 7, 8, 3, 5, 7, 5 };
int f[8][5];
int i,j;
for(i=0; i<8; i++) {
f[i][0] = a[i];
f[i][1] = b[i];
f[i][2] = c[i];
f[i][3] = d[i];
f[i][4] = e[i];
}
///输出结果
for(i=0; i<8; i++) {
for(j = 0; j < 5; j++)
printf("%2d", f[i][j]);
printf("\n");
}
return 0;
}
测试结果