#include <stdio.h>
#include <math.h>
void main()
{
int n;
double a[2],x,y;
printf("\nPlease enter x,n:");
scanf("%lf,%d",&x,&n);
while(x<1.0 || x>2.0 || n<0 || n>10)
{ printf("\nInvalid data (1.0<=x<=2.0,0<n<=10)\n\nPlease enter x,n:");
scanf("%lf,%d",&x,&n);
}
/**/
/**/
printf("\nResult: a[0]=%f,a[1]=%f",a[0],a[1]);
}
1 个回答
开心的记忆
赞同来自 :
#include <stdio.h>
#include <math.h>
void main()
{
int n;
double a[2],x,y;
printf("\nPlease enter x,n:");
scanf("%lf,%d",&x,&n);
while(x<1.0 || x>2.0 || n<0 || n>10)
{ printf("\nInvalid data (1.0<=x<=2.0,0<n<=10)\n\nPlease enter x,n:");
scanf("%lf,%d",&x,&n);
}
/**/
/**/
printf("\nResult: a[0]=%f,a[1]=%f",a[0],a[1]);}
fun(x)=((2n+1)x^n)/n(n+1)
=(2n+1) ^n/(n+1)